assumed_throwaw 3 hours ago

Tangential, but the complexity and over-head of the malloc abstraction is precisely what made me very intrigued by "stack-only" languages, such a recently published Goose. There is something very elegant and exciting about the idea of (almost) completely getting rid of it. Just as modern programming languages have developed good ergonomics that replaces a garbage collector, the same could hopefully be done to replace heap-allocated memory.

  • nialv7 3 hours ago

    the stack is just a bump allocator. the unique thing about stack-only languages is lifetime management, not really how they allocate.

    • saagarjha 3 hours ago

      A stack only language that called into malloc to service allocations would not be very interesting.

  • jacquesm 2 hours ago

    Most stack oriented languages also have a heap.

  • smashspectacle 2 hours ago

    This is actually what first drew me to zig. Most people talk about error handling, but the explicit allocator handling and making choosing an allocator a deliberate consideration has pushed me to better coding habits in general. I don't think it is possible or practical to completely abandon heap-allocated memory, but explicitly choosing between allocation types and styles that most precisely fit a job has great potential for meeting that spirit.

    • EPWN3D 1 hour ago

      I don't think we can get rid of heap memory, but I do think we can get rid of a shared heap.

  • connicpu 1 hour ago

    Avoiding the heap entirely isn't required and will prevent you from working with substantial amounts of data. The real key is to allocate all the memory you need up front and use that large block for a long duration.

    • packetlost 35 minutes ago

      > Avoiding the heap ... will prevent you from working with substantial amounts of data

      This isn't really true of Goose, it's avoiding 'the heap' in the C sense, not in the OS allocated pages of memory sense. One is a programming abstraction provided by the other, but GP is only talking about the programming abstraction. I have never encountered a program that couldn't have memory be explicitly tied to lexical scope, but it can result in less efficient use of it in some cases.

      Goose is almost, but not exactly the "allocate all your stuff at the beginning" the programming language. It's honestly the most exciting language I've seen in quite some time.

  • eschneider 1 hour ago

    Embedded programming has taught me that almost anything can be a stack-only language if you want it to be, even C++. :)

K0IN 1 hour ago

When getting into wasm when it was new and had clang support, I wrote my own libc and malloc, which was so a great learning all these low level functions and tricks (free lists for example), I also like that I can read wasm quite well, and tooling is good to just return a .wat and read it.

0xbadcafebee 1 hour ago

This shows you how you could "secure" memory code in C by using more robust implementations of these functions. But it doesn't show you that you don't even need them anyway. I think in my entire career I've only used dynamic memory in C twice. The rest of the time I use functions with static allocations, buffers, unrolled loops, etc. Maybe it's paranoia, or habits from embedded programming, or being a control freak... But my C programs don't get memory leaks or crash from memory issues.

  • hansvm 49 minutes ago

    You can secure part of C with robust memory-handling functions. So long as people are using --> and ++ to parallel iterate through buffers where they have to pass the right length around separate from its pointer though, you're not going to fix it all.

OhMeadhbh 1 hour ago
   One of  my pet  peeves is  when people,  trying to  make a
   point, use code  that doesn't compile.  I  mean, it's fine
   when you're sketching  out code on a white  board.  But on
   an  article you've  had  time to  prepare,  it's a  little
   annoying.

   Take for instance, this code fragment:

   .. static void *ptrs[1000];
   .. 
   .. int main(void) {
   ..     for (int i = 0; i < 1000; i++)
   ..         ptrs[i] = malloc(16);
   ..     }
   ..  }

   I'm pretty sure what they //meant// to write was:

   .. #include <stdlib.h>
   ..
   .. static void *ptrs[1000];
   .. 
   .. int main(void) {
   ..     for (int i = 0; i < 1000; i++)
   ..         ptrs[i] = malloc(16);
   ..     }
   ..     return( 0 );
   ..  }

   I  understand why  the  author produced  the  code on  top
   instead of the code at the bottom.  The code on the bottom
   includes  features extraneous  to  the conversation.   The
   include  directive  and  return statement  only  serve  to
   distract from the point the author is making.

   If you read far enough down,  you'll see he has links to a
   broken GitHub  repo presumably  with code  fragments.  (or
   maybe  GitHub itself  is  broken today  or  it decided  it
   didn't  like me  trying to  access the  repo from  an AT&T
   fiber line.)

   I'm sure when GitHub decides to behave and serve bits like
   it's supposed to, there will be compilable code so readers
   can understand  the author's intent within  the context it
   was intended to be viewed.

   Which is to say:

   1. It's probably  okay to have only code  fragments in the
      main part  of your  discussion.  Please provide  a note
      that  there is  code which  shows your  snippet in  the
      context  of a  compilable program.   And put  that note
      somewhere near the code fragment.

      Or... consider putting  a note at the  beginning of the
      article saying  something like "Compilable  versions of
      code  fragments  in this  article  are  available at  a
      GitHub  repository  referenced  at the  bottom  of  the
      page."

   2. Do  not depend on  GitHub to hold your  code fragments.
      You do not  know when it will be down  or which readers
      it will randomly decide to block.

   3.  I really  do  think  you should  include  more of  the
      "layout"  code.   When   reading  "The  Address  Space"
      section,   it  was   unclear  where   the  initialized,
      uninitialized and local came from.  I initially thought
      the  author was  using a  version of  C I  had not  yet
      encountered that defined these symbols.

   4.  Since  the code  uses  ``sbrk()``,  the author  should
      probably have  cautioned readers  the code  isn't POSIX
      compliant, but should compile  and run on Linux systems
      using gcc.   There's a  comment about  demonstrating it
      with  glibc, but  I think  that's not  a strong  enough
      warning since you can  compile programs with clang that
      are intended to link against glibc.
      
      I doubt there  are many QNX users out  there who expect
      random code from  the internet to run  on their systems
      without alteration, but it  seems good form to describe
      the environment you are targeting.

      Now I'm wondering if this is expected to work on Darwin
      as well as Linux.

   5.  It  might  be  a  decent  idea  to  order  the  SHOW()
      statements in  the code in "The  Address Space" section
      to follow  the order  of the diagram  at the  bottom of
      that section:

      .. SHOW( "local (stack)", &local );
      .. SHOW( "printf (libc)", printf );
      .. SHOW( "program break", sbrk(0) );
      .. SHOW( "malloc(16) (heap)", malloc(16) );
      .. SHOW( "uninitialised (bss)", &uninitialised);
      .. SHOW( "initialised (data)", &initialised );
      .. SHOW( "main(text)", main );

   6.  In  the  "Chunks  and  Headers"  section,  it  may  be
      interesting to mention what the flags in the allocation
      headers actually mean.

   7. glibc does late fill,  right?  I can't remember.  If it
      does,  it might  be  useful to  mention  in the  Demand
      Paging section since it affects the program logic.
   
   Now that I've yelled at the  cloud a bit, allow me to say,
   I enjoyed the article.  Things I liked:

   1. The author  used the exact strace command  they used to
      produce  the  output  discussed  in  the  text  of  the
      article.

   2. The graphics are quite nice.

   3. Despite grousing about  fragments being fragments, they
      do a good job of illustrating points made in the text.

   EDIT: After complaining about  GitHub not being available,
   it's finally come back.  The web interface is still borked
   for me, but  I can clone the repo mentioned  at the bottom
   of the page and view the local copy of the source.
amelius 3 hours ago

If the DRAM scarcity continues, not much.

  • xnickb 3 hours ago

    It's a consumer market scarcity. Since you're supposed to run everything on rented hardware, own nothing and be happy, I'd expect the malloc to be the right place to invest into once it is IPO.

    • colejohnson66 51 minutes ago

      MaaS (malloc as a service)? Everytime your serverless function needs to allocate, you pay some fraction of a penny?

TZubiri 3 hours ago

like many C functions you must remember that C is not low level, you won’t learn how memory is allocated by inspecting malloc() anymore than you would learn how characters are printed to the screen by reading printf() or how a file is written by reading write().

you will only learn about the thin or heavy wrapper that C is responsible for, the real magic is happening in the kernel and the device firmware

  • Someone 2 hours ago

    Malloc needs the kernel to obtain memory, but in any reasonable implementation (you do not want to make a syscall for every malloc and free) is mostly user space, and studying that will tell you a lot about how your malloc works.

  • foobarian 2 hours ago

    Disagree, I found malloc source useful, and writing a toy allocator especially useful because you learn about the brk() syscall which is a great breadcrumb into kernel land and a great bridge to connect the memory mapping lessons from computer architecture with application code.

    • stevekemp 2 hours ago

      Depending on how low-level you're going, you don't even need to call brk.

      My toy stop/copy GC and allocation routines just have this:

          %define HEAP_SIZE (4 * 1024 * 1024 * 1024)
      
          .section bss
          ;;
          ;; Two heaps so we can flip-flop between them
          ;;
          heap_a:
              resb HEAP_SIZE
          heap_a_end:
          heap_b:
              resb HEAP_SIZE
          heap_b_end:
      

      Of course there are other syscalls involved in my compiler/runtime, but for memory allocations the static area sufficed for me.

    • Joker_vD 1 hour ago

      > and writing a toy allocator especially useful because you learn about the brk() syscall

      Nobody in their right mind (except musl) use brk(2) nowadays; mmap(2) is pretty much universally accessible, and brk() has been non-portable for more than 20 years already (POSIX ditched it in 2001) anyhow. For goodness sake, stop keeping this stupid API from VM-lacking PDP-7 alive, and let it go away!

      Edit: also, I have no idea how musl even uses it:

          uintptr_t new = ctx.brk + pagesize;
          int need_guard = 0;
          if (!ctx.brk) {
              need_guard = 1;
              ctx.brk = brk(0);
              // some ancient kernels returned _ebss
              // instead of next page as initial brk.
              ctx.brk += -ctx.brk & (pagesize-1);
              new = ctx.brk + 2*pagesize;
          }
          if (brk(new) != new) {
              ctx.brk = -1;
          } else {
              if (need_guard) mmap((void *)ctx.brk, pagesize,
                      PROT_NONE, MAP_ANON|MAP_PRIVATE|MAP_FIXED, -1, 0);
              ctx.brk = new;
              ctx.avail_meta_areas = (void *)(new - pagesize);
              ctx.avail_meta_area_count = pagesize>>12;
              need_unprotect = 0;
          }
      

      That's... not what brk() returns; it returns 0 on success and -1 on failure. Huh?

      • roelschroeven 32 minutes ago

        When you call brk() from a user program you use the lib wrapper, and that does indeed return 0 on success and -1 on failure. But the actual Linux system call, which I presume is what musl calls, returns the current break on failure instead of -1.

        See the NOTES section in man brk(2):

        > C library/kernel differences

        > The return value described above for brk() is the behavior provided by the glibc wrapper function for the Linux brk() system call. (On most other implementations, the return value from brk() is the same; this return value was also specified in SUSv2.) However, the actual Linux system call returns the new program break on success. On failure, the system call returns the current break. The glibc wrapper function does some work (i.e., checks whether the new break is less than addr) to provide the 0 and -1 return values described above.

    • netbsdusers 51 minutes ago

      These days brk and sbrk have fallen from grace (and I think even some Unix-likes no longer provide them as general mechanisms, at least I don't think macOS does) - mmap is usually favoured.

  • netbsdusers 53 minutes ago

    Notwithstanding that most kernels today are written almost entirely in C anyway, you'll see learn a great deal about memory allocation by inspecting malloc().

    The usual division of labour in most operating systems is the kernel manages the virtual memory and physical pages and provides a mechanism for coarse page-aligned allocation of virtual address for userland. These coarse mappings userland (malloc or something else) is responsible for carving up, and in that is much design space. Just look at mimalloc for example.

    The kernel's own page allocation is often very simple (many get by with a simple freelist, some use buddies.) The allocators for the kernel's own datastructures are usually relatively simple at least conceptually. Bonwick explains the slab allocator - the almost universally acknowledged queen of all kernel memory allocators and mother of those of Linux, BSD, and beyond - in a 12-page paper.

    As for the firmware there's basically nothing of an ongoing role for it after the kernel is in charge. Its role is limited for the most part to providing the kernel with a map of the physical addres space.

    By reading malloc() you will not learn everything about allocation - that is a problem that spans multiple layers - but you will certainly learn a lot about it. To call it a mere wrapper is not reasonable.

  • 100111011111 48 minutes ago

    Well, yes, but its low level , no matter what, I mean whats left thats lower?